Question

Помогите 220 решить плиз

Answer 1

а)f'(x)=12(8x^5-5x^8)^11×(40x^4-40x^7)=480x^4×(8x^5-5x^8)^11×(1-x³)
б)f'(x)=1/9×27(1/9-3x³)^26×(-9x²)=-27x²(1/9-3x³)^26
в)f'(x)=10(4x^10-5x)^9×(40x^9-5)=5(4x^10-5x)^9×(8x^9-1)
г)f'(x)=130(x^5-4x^4)^129×(5x^4-16x³)=130x³(x^5-4x^4)^129×(5x-16)