Question

Срочно!!!!!!!!!! №544 (б)

Answer 1

$\sqrt{1 \frac{3}{8} } * \sqrt{5 \frac{1}{2} } - \sqrt{ \frac{12,5^{2}-3,5 ^{2} }{2*128} } = \sqrt{ \frac{11}{8} * \frac{11}{2} } - \sqrt{ \frac{(12,5-3,5)(12,5+3,5)}{2 ^{8} } } = \sqrt{ \frac{11^{2} }{16} } - \sqrt{ \frac{9*16}{ 2^{8} } } = \frac{11}{4} - \frac{3*4}{2^{4} } = \frac{44}{16} - \frac{12}{16} = \frac{32}{16} =2$