Question

решите неравенство:
log7 (3x-1)>=log7 (2x+2)

Answer 1

$log_7 (3x-1) \geq log_7 (2x+2) \\ \\ 3x-1 \geq 2x+2 \\ \\ x \geq 3$

ОДЗ:
$\left \{ {{3x-1 \ \textgreater \ 0} \atop {2x+2 \ \textgreater \ 0}} \right. \\ \\ \left \{ {{x \ \textgreater \ \frac{1}{3} } \atop {x \ \textgreater \ -1}} \right.$

Ответ:
$x \geq 3$