Question

Найти производную функции y=х^3/(х^2-3)

Answer 1

$y=\frac{x^3}{x^2-3}\\\\y'=\frac{3x^2(x^2-3)-x^3\cdot 2x}{(x^2-3)^2}=\frac{3x^4-9x^2-2x^4}{(x^2-3)^2}=\frac{x^4-9x^2}{(x^2-3)^2}= \frac{x^2(x-3)(x+3)}{(x^2-3)^2}$