Question

Решите 4 и 5 номер!!!!

Answer 1

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Answer 2

4) $( \sqrt{6} - \sqrt{2}) ^{2}*(8+ \sqrt{48})=(6 - 2 \sqrt{12} +2)(8+ \sqrt{16*3})=$$(8-2 \sqrt{4*3})(8+4 \sqrt{3})=(8-4 \sqrt{3})(8+4 \sqrt{3})=8 ^{2} -(4 \sqrt{3} ) ^{2}=64-48$$=16$

5) (17 - x)(x² + 5x) = 0
x(17 - x)(x + 5) = 0
или   x₁ = 0          или   17 - x = 0        или  x + 5 = 0
                                      x₂ = 17                   x₃ = - 5
Среднее арифметическое корней уравнения равно:
$\frac{0+17-5}{3} = \frac{12}{3}=4$