Question

Решите уравнение 3y^2+2y=0

Answer 1

$y(3y + 2) = 0 \\ y1 = 0 \\ 3y + 2 = 0 \\ y2 = - \frac{2}{3}$

Answer 2

$y*(3y+2)=0$
$y=0$
$3y+2=0$
$y=0$
$3y=-2$
$y=- \frac{2}{3}$
$y_1=- \frac{2}{3} ;y_2=0$