Question

$\frac{ x^{2} +1}{x+1} =1$

Answer 1

$\frac{ x^{2} + 1 }{x+1} = 1$

$\frac{ x^{2} +1 }{x+1} = 1$ $x \neq -1$

x² + 1 = x + 1

x² + 1 - x - 1 = 0

x(x - 1) = 0

x = 0
x - 1 = 0

x = 0
x = 1
$x_{1} = 0, x_{2} = 1$