Question

\left \{ {{5 ^{2x+y}=125 } \atop {4 ^{(x-y)} ^{2} =1 }} \right.
$\left \{ {{5 ^{2x+y}=125 } \atop {4 ^{(x-y)} ^{2} =1 }} \right.$

Answer 1

$\left \{ {{5 ^{2x+y}=125 } \atop {4 ^{(x-y)} ^{2} =1 }} \right. \\\\ \left \{ {{5 ^{2x+y}=5^3 } \atop {4 ^{(x-y)} ^{2} =4^0 }} \right. \\\\ \left \{ {{2x+y=3 } \atop {(x-y)} ^{2} =0 }} \right. \\\\ \left \{ {{2x+y=3 } \atop {x-y=0 }} \right. \\\\ \left \{ {{2x+y=3 } \atop {3x=3 }} \right. \\\\ \left \{ {{2x+y=3 } \atop {x=1 }} \right. \\\\ \left \{ {{2+y=3 } \atop {x=1 }} \right. \\\\ \left \{ {{y=1 } \atop {x=1 }} \right.$