Question

Пж решите очень надо !!

Answer 1

(c¹⁰ + u¹⁰)² - (c¹⁰ - u¹⁰)² - c²u² = c²⁰ + 2c¹⁰u¹⁰ +u²⁰ - c²⁰ +2c¹⁰u¹⁰ - u²⁰ - c²u² =
= 4c¹⁰u¹⁰ - c²u² = c²u²(4c⁸u⁸ - 1)=c²u²(2c⁴u⁴-1)(2c⁴u⁴ + 1)

Answer 2

$(c^{10}+u^{10})^2-(c^{10}-u^{10})^2-c^2u^2=(c^{10}+u^{10}-c^{10}+u^{10})* \\ \\ (c^{10}+u^{10}+c^{10}-u^{10})-c^2u^2=2u^{10}*2c^{10}-c^2u^2=4c^{10}u^{10}-c^2u^2 \\ \\ =c^2u^2*(4c^8u^8-1)=c^2u^2*(2c^4u^4-1)*(2c^4u^4+1)$⁰