Question

sin^3x+sin^2xcosx - 3sinxcos^2x - 3cos^3x =0

Answer 1

разделите на cos³x и введите замену t=tgx: t³-t²+3=3t <=> t²(t-1)-3(t-1)=0, t=1 или t=√3, t=-√3  x=π/4+πn x=π/3+πk x=-π/3+πl