Question

помогите матика #1057 #1060

Answer 1

№1057
а) (-3,25+(-1$\frac{3}{4}$))+(-1$\frac{2}{3} +(-1 \frac{4}{9} ))=-1 \frac{8}{9}$
1) -3,25=-3 \frac{3}{4}[/tex]
$-3 \frac{1}{4}-1 \frac{3}{4}=-4 \frac{4}{4}=-5$
2)$-1 \frac{2}{3}^{3} -1 \frac{4}{9}=-1 \frac{6}{9}=-2 \frac{10}{9} \frac{x}{y} =-3 \frac{1}{9}$
3)-5-3$\frac{1}{9}=-1 \frac{8}{9}$
б)(-$\frac{2}{5}+(- \frac{2}{15}))+(-1,85+(1,35))=-3 \frac{1}{9}$$1 )- \frac{2}{3} ^{5}- \frac{2}{15}=- \frac{10}{15}- \frac{2}{15}=- \frac{12}{15}$$2)-1 \frac{2}{3}^{3}-1 \frac{4}{9}=-1 \frac{6}{9}-1 \frac{4}{9}=-2 \frac{10}{9}=-3 \frac{1}{9}$
№1060
$\frac{2}{3}^{3} x+ \frac{4}{9} x=3,2$$\frac{6}{9} x+ \frac{4}{9} x=3,2$$\frac{10}{9} x=3,2$$x=2 \frac{11}{9}: \frac{10}{9}$