Question

найти y'(x)=? y(x)=2x+3\x^2+1

Answer 1

$y=\frac{2x+3}{x^2+1} \\ y'=\frac{2(x^2+1)-2x(2x+3)}{(x^2+1)^2}=\frac{2x^2+2-4x^2-6x}{(x^2+1)^2}=\frac{-2x^2+2-6x}{(x^2+1)^2}$