Question

y=sin(2x-pi/3)

найти производные

Answer 1

$y=Sin(2x - \frac{ \pi }{3} )\\\\y'=[Sin(2x- \frac{ \pi }{3} )]'=Cos(2x- \frac{ \pi }{3})*(2x- \frac{ \pi }{3} )'=2Cos(2x- \frac{ \pi }{3})$

Answer 2

$y = \sin(2x - \frac{\pi}{3} ) \\ y ' = \cos(2x - \frac{\pi}{3} ) \times (2x - \frac{\pi}{3} )'= \\ = \cos(2x - \frac{\pi}{3} ) \times 2 = \\ = 2\cos(2x - \frac{\pi}{3} )$