Question

СРОЧНО!!!!!Решите, пожалуйста❗️❗️❗️
7^x+2-7^x+1-2*7^x>2^x/3+1+2^x/3-1

Answer 1

$7^{x+2}-7^{x+1}-2*7^{x}\ \textgreater \ 2^{\frac{x}{3}+1}+2^{\frac{x}{3}-1} \\ 7^{x}*7^{2}-7^{x}*7^{1}-2*7^{x}\ \textgreater \ 2^{\frac{x}{3}}*2^{1}+2^{\frac{x}{3}}*2^{-1} \\ 7^{x}*(7^{2}-7-2)\ \textgreater \ 2^{\frac{x}{3}}(2+\frac{1}{2}) \\ 7^{x}*40 \ \textgreater \ 2^{\frac{x}{3}}*\frac{5}{2} \\ 7^{x}*80 \ \textgreater \ 2^{\frac{x}{3}}*5 \\ 7^{x}*16 \ \textgreater \ 2^{\frac{x}{3}} \\ 7^{x}\ \textgreater \ \frac{2^{ \frac{x}{3}}}{16} \\ \frac{7^{x}}{2^{\frac{x}{3}}}}\ \textgreater \ \frac{1}{16} \\ (\frac{7}{2^{\frac{1}{3}}}})^x\ \textgreater \ \frac{1}{16} \\ x \ \textgreater \ log_{\frac{7}{2^{\frac{1}{3}}}}} \frac{1}{16}$
$x \ \textgreater \ \frac{ln(\frac{1}{16})}{ln{\frac{7}{2^{\frac{1}{3}}}}}} \\ x \ \textgreater \ \frac{ln(2^{-4})}{ln(7)-ln({2^{\frac{1}{3}})}}}}\\ x \ \textgreater \ \frac{-4*ln(2)}{ln(7)- \frac{1}{3} ln({2)}}\\ x \ \textgreater \ \frac{-12*ln(2) }{3*ln(7)-ln({2)}}\\ x \ \textgreater \ \frac{-12ln(2)}{3ln(7)-ln({2)}}\\ x \ \textgreater \ \frac{12ln(2)}{ln({2)-3ln(7)}}$