Question

2(х-2)(х+2) = (х-4)(х+4)+(х-3)(х+3)+х
помогите уравнение решить :D

Answer 1

$2{x}^{2} - 8= {x}^{2} - 16 + {x}^{2} - 9 + x \\ 2 {x }^{2} - 2 {x}^{2} - x = - 25 + 8 \\ - x = - 17 \\ x = 17$

Answer 2

2 • (x - 2) • (x + 2) = (x - 4) • (x + 4) + (x - 3) •(x + 3) + x

2 • (x^2 - 4) = x^2 - 16 + x^2 - 9 + x

2x^2 - 8 = 2x^2 - 25 + x

-8 = -25 + x

- x = -25 + 8

-x = -17

x = 17

@iGeniusOX⚡