Question

[Алгебра] [Многочлены] Смотреть на СкринШот

Answer 1

$( \frac{1}{8} z^5- \frac{5}{6} )^2= \frac{1}{64} z^{10}-2* \frac{z^5}{8} * \frac{5}{6} + \frac{25}{36} = \frac{1}{64} z^{10}- \frac{5}{24} z^5+ \frac{25}{36}$