Question

(3x+5)(4x-1)=(6x-3)(2x-7) помогите решить уравнение

Answer 1

$(3x + 5)(4x - 1) = (12 {x}^{2} - 3x + 20x - 5) = (12 {x}^{2} + 17x - 5) \\ (6x - 3)(2x - 7) = (12 {x}^{2} - 42x - 6x + 21) = (12 {x}^{2} - 48x + 21) \\ 12 {x}^{2} + 17x - 5 = 12 {x}^{2} - 48x + 21 \\ - 26 = - (17 + 48)x \\ x = 26 \div 65 = 0.4$

Answer 2

$(3x+5)(4x-1)= \\ (6x-3)(2x-7) \\ 12 {x}^{2} + 20x - 3x - 5 = \\ 12 {x}^{2} - 6x - 42x + 21 \\ 12 {x}^{2} - 12 {x}^{2} + 17x + 48x = \\ 21 + 5 \\ 65x = 26 \\ x = \frac{26}{65}$