Question

(у-4) (у+6)
(4а+1) ( 2а - 3)
(2у- b) (4y+3b)

Answer 1

Решение:
1) (y - 4)·(y + 6) = y² + 6y - 4y - 24 = y² + 2y - 24;
2) (4a + 1)·(2a - 3) = 8a² - 12a + 2a - 3 = 8a² - 10a - 3;
3) (2y - b)·(4y + 3b) = 8y² + 6by - 4by - 3b² = 8y² + 2by - 3b².