Question

Log 5 (4x+1)=log5 (2x-1)

Answer 1

$\displaystyle\mathtt{\log_5(4x+1)=\log_5(2x-1);~\left\{{{4x+1=2x-1}\atop{\left\{{{4x+1\ \textgreater \ 0}\atop{2x-1\ \textgreater \ 0}}\right}}\right\left\{{{x=-1}\atop{\left\{{{x\ \textgreater \ -\frac{1}{4}}\atop{x\ \textgreater \ \frac{1}{2}}}\right}}\right}$

ответ: нет решений