Question

(9^x)^x+1*корень из 27^x-3=3

Answer 1

9^(x^2+x)*sqrt3^(3(x-3))=3
3^(2x^2+2x)*3^((3x-9)/2)=3
2x^2+2x+((3x-9)/2)=1
2(2x^2+2x)+3x-9=2
4x^2+4x+3x-9=2
4x^2+7x-11=0
D=49+176=225
x1= -7-15/8=-22/8= -2  3/4
x2=-7+15/8= 8/8= 1   

Answer 2

$((3^2) ^{x} ) ^{x+1} +((3^3) ^{1/2} ) ^{x-3} =3$
$3 ^{2x^2+2x+1,5x-4,5} =3$
2x²+3,5x-4,5-1=0
2x²+3,5-5,5=0
D=12,25+44=56,25
x1=(-3,5-7,5)/4=-11/4
x2=(-3,5+7,5)/4=1