Question

Разложите на множители

Answer 1

и)9(а+1)(а+1)-1
9а+9+9а+9-1
18а+17

Answer 2

и) = (3(а+1)-1))(3(а+1)+1) = (3а+3-1)(3а+3+1)=(3а+2)(3а+4)
к) = (2-5(х-3))(2+5(х-3)) = (2-5х+15)(2+5х-15) = (17-5х)(5х-13)
л) = (3(х+5) - (х-7))(3(х+5) +(х-7)) = (3х+15-х+7)(3х+15+х-7) = (2х+22)(4х+8) = 2(х+11)4(х+2) = 8(х+11)(х+2)
м) = (7(у-4) - 3(у+2))(7(у-4) + 3(у+2)) = (7у-28-3у-6)(7у-28+3у+6) = (4у-34)(10у-22) = 2(2у-17)2(5у-11) = 4(2у-17)(5у-11)