Предмет: Геометрия, автор: AHTOH196437

решите пожалуйста две задачи по геометрии, дам 30 балов

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Автор ответа: Lily491

задача 1:
1) рассмотрим треуг. ABE и DCE, у них:
BE=EC, AE=ED( по усл.), угол BEA=CED( как вертик.)
след. треуг. ABE=DCE(по двум сторонам и углу между ними)
2)из равенства треуг. следует, что угол BEA=CDE, эти углы накрест лежащие при прямых AB и DC И секущей AD, следовательно AB параллельно DC

Lily491: не за что

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