Question

надо перевети в однародныйчлен

Answer 1

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Answer 2

$(x + 3) ^{2} - 16 = (x + 3) {}^{2} - 4 {}^{2} = ( x + 3 + 4) \times (x + 3 - 4) = (x + 7) \times (x - 1)$