Question

Помогите, пожалуйста ♥️

Answer 1

1) 1-log³ₐb=(1-logₐb)*(log²ₐb+logₐb+1).
2) logₐb+log(b)a+1=logₐb+1/logₐb+1=(log²ₐb+logₐb+1)/logₐb.
3) logₐ(a/b)=logₐa-logₐb=1-logₐb.
4)(1-logₐb)(log²ₐb+logₐb+1)/((log²ₐb+logₐb+1)/logₐb)(1-logₐb))=logₐb.
Ответ: logₐb.