Question

решити на множенстве R систему неравенств  номер9

Answer 1

$1)\; \; \left \{ {{-3x\ \textgreater \ 9} \atop {4x\ \textless \ 1}} \right. \; \left \{ {{x\ \textless \ -3} \atop {x\ \textless \ 0,25}} \right. \; \to \; \; x\ \textless \ -3\\\\2)\; \; \left \{ {{11x+1 \geq -5} \atop {2-3x\ \textless \ 5}} \right. \; \left \{ {{11x \geq -6} \atop {3x\ \textgreater \ -3}} \right. \; \left \{ {{x \geq -\frac{6}{11}} \atop {x\ \textgreater \ -1}} \right. \; \; \to \; \; x \geq -\frac{6}{11}\\\\3)\; \; \left \{ {{3-4x\ \textgreater \ -5} \atop {6+9x \leq 1}} \right. \; \left \{ {{-4x\ \textgreater \ -8} \atop {9x \leq -5}} \right. \; \left \{ {{x\ \textless \ 2} \atop {x \leq -\frac{5}{9}}} \right. \; \; \to \; \; x \leq -\frac{5}{9}$

$4)\; \; \left \{ {{3x-6\ \textgreater \ 2x} \atop {2x-6\ \textgreater \ 5x}} \right.\; \left \{ {{x\ \textgreater \ 6} \atop {-6\ \textgreater \ -3x}} \right. \; \left \{ {{x\ \textgreater \ 6} \atop {x\ \textgreater \ 2}} \right. \; \; \to \; \; x\ \textgreater \ 6\\\\5)\; \; \left \{ {{2x+1 \leq 13} \atop {9-2x\ \textless \ x}} \right. \; \left \{ {{2x \leq 12} \atop {9\ \textless \ 3x}} \right. \; \left \{ {{x \leq 6} \atop {x\ \textgreater \ 3}} \right. \; \; \to \; \; 3\ \textless \ x \leq 6$