Question

Решите 39 номер!!!!!!

Answer 1

$[tex]log^2_5(x)+log_5(x)=2\\x\ \textgreater \ 0\\log_5(x)=t\\t^2+t=2\\t^2+t-2=0\\a+b+c=0\\t_1=1\\t_2=-2\\log_5(x)=1\\x=5\\log_5(x)=-2\\x=5^{-2}= \frac{1}{25}$[/tex]