Предмет: Геометрия, автор: Ingosh06

высота правильной четырехугольной пирамиды равна 12 см, а сторона основания 10 см

Ответы

Автор ответа: EpicArctic

в условии не указано, что находить надо, полагаю надо найти объем
V = S осн. * h * 1/3 (h - высота)
S осн. = 10^2 = 100 см^2
V = 100 * 12 * 1/3 = 1200 * 1/3 = 400 см^3

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