Question

ЛЮДИ В ЧАС ИДТИ НА МАТЕМАТИКУ А Я ЗАБЫЛА ПРО ПРИМЕР ЛЮДИ БУДТЕ ЛЮДЬМИ ПОМОГИТЕ!!!!!!!!!!!!!!!!!!!!!!!!!!!!1

Answer 1

1)2m/(m+4)+16/(m²-4m+16)-(m²-20m²)/(m+4)(m²-4m+16)=
=[2m(m²-4m+16)+16(m+4)-(m³-20m²)]/(m+4)(m²-4m+16)=
=(2m³-8m²+32m+16m+64-m³+20m²)/(m+4)(m²-4m+16)=
=(m³+12m²+48m+64)/(n+4)(m²-4m+16)=(m+4)³/(m+4)(m²-4m+16)=
=(m+4)²/(m²-4m+16)
2)(m+4)-12m/(m+4)=(m²+8m+16-12m)/(m+4)=(m²-4m+16)/(m+4)
3)(m+4)²/(m²-4m+16) * (m²-4m+16)/(m+4)=m+4
4)(m+4):(m+4)=1

Answer 2

$( \frac{2m}{m+4} + \frac{16}{m^2-4m+16}- \frac{m^3-20m^2}{m^3+64})(m+4- \frac{12m}{m+4} ):(m+4)=\\=( \frac{2m}{m+4}+ \frac{16}{m^2-4m+16} - \frac{m^3-20m^2}{(m+4)(m^2-4m+16)} ) * \frac{m(m+4)+4(m+4)}{m+4} * \frac{1}{m+4} =\\= \frac{2m(m^2-4m+16)+16(m+4)-(m^3-20m^2)}{(n+4)(m^2-4m+16)} * \frac{m^2+4m+4m+16-12m}{m+4} * \frac{1}{m+4}=\\= \frac{2m^3-8m^2+32m+16m+64-m^3+20m^2}{(m+4)(m^2-4m+16)}* \frac{m^2-4m+16}{m+4} * \frac{1}{m+4} = \\=\frac{m^3+12m^2+48m+64}{(m+4)(m^2-4m+16)} *\frac{m^2-4m+16}{m+4}$
$*\frac{1}{m+4}=\frac{(m+4)^3}{(m+4)(m^2-4m+16)} *\frac{m^2-4m+16}{m+4}*\frac{1}{m+4} =\\=\frac{(m+4)^2}{m^2-4m+16} *\frac{m^2-4m+16}{m+4}*\frac{1}{m+4}=\frac{m+4}{m+4}=1$