Question

ПОМОГИТЕ ПЛИИС 100 БАЛОВ
номер 997

Answer 1

$\frac{5}{8} x - ( \frac{1}{4} x - \frac{1}{12} y) + \frac{1}{3} y = \frac{5}{8} x - \frac{1}{4} x + \frac{1}{12} y + \frac{1}{3} y = \frac{3}{8} x + \frac{2}{12} y - \frac{5}{3} y = 11.4x - \frac{199}{12} y$
$9.4x + (2x - 11 \frac{3}{4} y) - 3 \frac{5}{9} y = 9.4x + (2x - \frac{33}{4} y) - \frac{5}{3} y = 9.4x + 2x - \frac{33}{4} y - \frac{5}{3} y = 11.4x - \frac{199}{12} y$
$2 \frac{1}{6} x - (7x - 1 \frac{3}{4} y) + 2 \frac{1}{4} y = \frac{1}{3} x - (7x - \frac{3}{4} y) + \frac{1}{2} y = \frac{1}{3} x - 7x + \frac{3}{4} y + \frac{1}{2} y = - \frac{20}{3} x + \frac{5}{4} y$
$3.5x + (6 \frac{1}{4} x - 7y) - 7y = 35x + (3 \times \frac{1}{2} x - 7y) - 7y = 3.5x + ( \frac{3}{2} - 7y) - 7y = 3.5x + \frac{3}{2} x - 7y - 7y = \frac{7}{2}x + \frac{3}{2} x - 14y = 5x - 11y$