Question

Помогите пожайлуста!!!срочно!!! (49х\у + 9у\х -42)• 1\(7х-3у)^2 при х =корень 15
У=корень 5\3

Answer 1

$( \frac{49x}{y} + \frac{9y}{x}-42)* \frac{1}{(7x-3y) ^{2} } = \frac{49 x^{2} +9 y^{2}-42xy }{xy}* \frac{1}{(7x-3y) ^{2} }= \frac{(7x-3y) ^{2} }{xy}*$$\frac{1}{(7x-3y) ^{2} }= \frac{1}{xy}$

$\frac{1}{ \sqrt{15}* \sqrt{ \frac{5}{3} }}= \frac{1}{ \sqrt{15* \frac{5}{3} } } = \frac{1}{ \sqrt{25} }= \frac{1}{5} =0,2$