Question

Решите уравнение $\frac{27}{x} - \frac{20}{x-3} = \frac{1}{6}$

Answer 1

$\frac{27}{x}- \frac{20}{x-3} = \frac{1}{6} \\ \\ \frac{27x-81-20x }{x^2-3x} = \frac{1}{6} \\ \\ x^2-3x = 6*(7x-81) \\ x^2-45x+486 = 0 \\ D = 45^2-4*486 = 81 \\ x_1=27 \\ x_2=18$