Question

Помогите решить.
Срочно по образцу

Answer 1

$1)\; \; 25-n^2=5^2-n^2=(5-n)(5+n)\\\\2)\; \; 36p^2-100m^2=(6p)^2-(10m)^2=(6p-10m)(6p+10m)\\\\3)\; \; 81a^2-9b^2=(9a)^2-(3b)^2=(9a-3b)(9a+3b)\\\\4)\; \; 416-p^2=16\cdot 26-p^2=(4\sqrt{26})^2-p^2=\\\\=(4\sqrt{26}-p)(4\sqrt{26}+p)$