Question

help, срочно надо...

Answer 1

$\displaystyle 2^{ \frac{x-3}{x}}\ \textgreater \ 2 \\ \\ \frac{x-3}{x}\ \textgreater \ 1 \\ \\ odz:x \neq 0 \\ \\ \frac{x-3-x}{x}\ \textgreater \ 0 \\ \\- \frac{3}{x}\ \textgreater \ 0 \\ \\ x\ \textless \ 0$

Ответ: x∈(-∞; 0)