Question

Решите задачу
m р-ра(H3PO4)=120г
W%(H3PO4)=15%
m(H2O)=150г
Найти
W2%(H3PO4)-?

Answer 1

m(H3PO4)=120г*0,15=18г
m2(р-ра)=120г+150г = 270г
ω2% =
$100\% \times \frac{18}{270} = 6.6\%$