Question

(5×-1)(×+2)+3(×-4)(×+4)=2(2×+3)²-8
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Answer 1

Решение:
$(5x - 1)(x + 2) + 3(x - 4)(x + 4) = 2(2x + 3 {)}^{2} - 8 \\ 5 {x}^{2} + 10x - x - 2 + 3( {x}^{2} - 16) = 2(4 {x}^{2} + 6x + 9) - 8 \\ 5 {x}^{2} + 9x - 2 + 3 {x}^{2} - 48 = 8 {x}^{2} + 12x + 18 - 8 \\ 8 {x}^{2} + 9x - 50 = 8 {x}^{2} + 12x + 10 \\ 12x - 9x = - 60 \\ 3x = - 60 \\ x = - \frac{60}{3} \\ x = - 20$
Ответ: х = -20