Question

-(4/3)x²+12=0
умоляю, решите уравнение

Answer 1

-4/3х^2 = -12
x^2 = 9
x = +3 -3

Answer 2

$- \frac{4}{3} x^2+12=0$
$- \frac{4}{3}x^2=-12$
$x^2=9$
$x=\pm 3$
$x=3$
$x=-3$
$x_1=-3; x_2=3$