Question

Решите задания по алгебре а то башка не варит

Answer 1

$\frac{9 ^{log _{3}7 } }{27 ^{log _{3} 5} }+4 ^{ \frac{1}{log _{25}16 } }= \frac{9 ^{log _{9}49 } }{27 ^{log _{27}125 } }+4 ^{log _{16}25 } = \frac{49}{125}+4 ^{log _{4}5 } =0,392+5 =$$5,392$

$3 ^{log _{3}14-log _{3} 7 } +log _{ \sqrt{3} }27=3 ^{log _{3} \frac{14}{7} } +2log _{3}27=3 ^{log _{3}2 } +2*3=2+6=8 2log _{5}15-4log _{25}3=2(log _{25}225 -log _{25} 9)=2log _{25} \frac{225}{9}=2log _{25}25=2$

$log _{27}15- \frac{1}{3} log _{3}5=log _{27}15-log _{27}5=log _{27} \frac{15}{5} =log _{27}3 = \frac{1}{3}$