Question

Срочно пжпжпжпжжпжпжп 2 и 3 срочно пж

Answer 1

- 0,4a(2a² + 3)(5 - 3a²) = - 0,4a(10a²  - 6a⁴ + 15 - 9a² ) = - 0,4a(a² - 6a⁴ +15)=
= - 0,4a³ + 2,4a⁵ - 6a

2x(x - 1) - 3(x - 1) = (x - 1)(2x - 3)

ab + ac + 4b + 4c = (ab + ac) + (4b + 4c) = a(b + c) + 4 (b + c) = (b + c)(a + 4)