Question

Разложите на множители.

25a³-1
125+b³
1-36y³
c³-4ac+4a³

Answer 1

25a³-1=(25^(1/3)a)^3-1=(a*25^(1/3)-1)(a^2*25^(2/3)+a*25^(1/3)+1)
25a³-1=1/5 *(5a-5^(1/3))(25a^2+5a*5^(1/3)+5^(2/3))

125+b^3=5^3+b^3 =(5+b)(25-5b+b^2)

1-36y^3=1-(y*36^(1/3))^3=(1-y*36^(1/3))(1+y*36^(1/3)+y^2*36^(2/3))
1-36y^3=1/6 *(6^(1/3)-6y)(36y^2+6y*6^(1/3)+6^(2/3))

c³-4ac+4a³= не раскладывается на множители