Question

(x-2x)^2-(x^2-2x)+x^2=12
помогите

Answer 1

$2x+x^2=12$
$2x+x^2-12=0$
$\frac{-b\pm \sqrt{b^2-4(ac)} }{2a}$
$\frac{-2\pm \sqrt{2^2-4*(1*-12)} }{2*1}$
$x=-1\pm \sqrt{13}$
$x=-1\pm \sqrt{13}$
$x \approx 2.60555127; -4.60555127$