Question

1/3+2 (корень)2+1/3-2 (корень)2

Answer 1

$\dfrac{1}{3+2\sqrt{2}}+\dfrac{1}{3-2\sqrt{2}}=\dfrac{3-2\sqrt{2}+3+2\sqrt{2}}{(3+2\sqrt{2})(3-2\sqrt{2})}=\dfrac{6}{3^2-(2\sqrt{2})^2}=\dfrac{6}{9-8}=6$