Question

Решите уравнение:
3sin^2x+sinxcosx-2cos^x=0

Answer 1

$3sin^2x+sincosx-2cos^2x=0/:cos^2x \neq 0\\ 3tg^2x+tgx-2=0\\ 1. \ tgx=-1\\ x= - \frac{ \pi }{4} + \pi n\\ 2. \ tgx= \frac{2}{3} \\ x=arctg \frac{2}{3} + \pi n$