Question

№25, пожалуйста.
Заранее спасибо.

Answer 1

1)y^2+y-12/y^2+8y+16
y^2+4y-3y-12/(y+4)^2
y (y+4)-3(y+4)/(y+4)^2
(y-3)(y+4)/(y+4)^2
y-3/y+4
2)4m^2+12m+9/2m^2-m-6
(2m+3)^2/2m^2+3m-4m-6
(2m+3)^2/m(2m+3)-2(2m+3)
(2m+3)^2/(m-2)(2m+3)
(2m+3)/m-2
3)a^3+a^2-a-1/a^2+2a+1
a^2*(a+1)-(a+1)/(a+1)^2
(a^2-1)(a+1)/(a+1)^2
(a-1)(a+1)(a+1)/(a+1)^2
(a-1)(a+1)^2/(a+1)^2
a-1

Answer 2

1
y²+y-12=0
y1+y2=-1 U y1*y2=-12⇒y1=-4 U y2=3
(y²+y-12)/(y²+8y+16)=(y+4)(y-3)/(y+4)²=(y-3)/(y+4
2
2m²-m-6=0
D=1+48=49
m1=(1-7)/4=-3/2 U m2=(1+7)/4=2
(4m²+12m+9)/(2m²-m-6)=(2m+3)²/(2m+3)(m-2)=(2m+3)/(m-2)
3
(a³|a²-a-1)/(a²+2a+1)=[a²(a+1)-(a+1)]/(a+1)²=(a+1)(a²-1)/(a+1)²=
=(a-1)(a+1)/(a+1)=a-1