Question

1)1+x^2=-2x
2)-x^2=9-6x

Answer 1

$1+ x^{2} =-2x \\ x^{2} -2x+1=0 \\ a=1; b=-2; c=1 \\ D= b^{2}-4ac=4-4=0 \\ x= \frac{-b}{2a}= \frac{2}{2}=1$
Ответ: $x=1$
$- x^{2} =9-6x \\ - x^{2} +6x-9=0 \\ a=-1; b=6; c=-9 \\ D= b^{2} -4ac=36-4*9=36-36=0 \\ x= \frac{-b}{2a}= \frac{-6}{-2} =3$
Ответ: $x=3$