Предмет: Физика, автор: апп20

масса гири подвешеннои к пружине динамомтра равна m=30 г.Какую по модулю силу F покажет динамометр ,если его перемещать равномерно вертикально вниз

Ответы

Автор ответа: sokolovvovikn

5

F=m*g=0,03*10=0,3 H
...............................................

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