Question

Найти производную функций F(x)=5x-2/sinx ; f(x)=tgx/3+x ; f(x)=x-2/ctgx

Answer 1

$1)f'(x)=5- frac{(2)'sin(x)-2(sin(x))'}{sin^2(x)} =5+ frac{2*cos(x)}{sin^2(x)}$
$2)f'(x)= frac{1}{3*cos^2(x)}+1 \ 3)f'(x)= 1- frac{x(2)'ctg(x)-2(ctg(x))'}{ctg^2(x)} =1+ frac{2}{ctg^2(x)*sin^2(x)}$