Question

(а^2+4а)^2-а^2*(а-2)(а+2)-4а^2*(2а-1)

16у+2*(у-4)^2

(Х+5)^2-5х*(2-х)
Решите умоляююю

Answer 1

1) (a²+4a)²-a²(a-2)(a+2)-4a²(2a-1)= a⁴+16a²+8a³-a²(a²-4)-8a³+4a²= a⁴+16a²+8a³-a⁴+4a²-8a³+4a²= 8a²
2) 16y+2(y-4)²= 16y+2(y²+16-8y)= 16y+2y²+32-16y= 2y²+32
3) (x+5)²-5x(2-x)= x²+25+10x-10x+5x²= 6x²+25