Question

решите не равенство.
n^2-(n+1)^2 >2

Answer 1

$n^2-(n+1)^2\ \textgreater \ 2 \\ n^2-n^2-2n-1\ \textgreater \ 2 \\ -2n-1-2\ \textgreater \ 0 \\ -2n-3\ \textgreater \ 0 \\ 2n+3\ \textless \ 0 \\ 2n\ \textless \ -3 \\ n\ \textless \ -1.5$

Ответ : (-∞;-1.5)