Question

мне очень срочно и надо расписать ну типо
x=

Answer 1

a)
$(x- \frac{1}{4} )+3 \frac{1}{12} =7 \frac{1}{3} \\ \\ x- \frac{1}{4} =7 \frac{1}{3} -3 \frac{1}{12} \\ \\ x- \frac{1}{4} =7 \frac{4}{12} -3 \frac{1}{12} \\ \\ x- \frac{1}{4} =4 \frac{3}{12} \\ \\ x- \frac{1}{4} =4 \frac{1}{4} \\ \\ x=4 \frac{1}{4} + \frac{1}{4} \\ \\ x=4 \frac{2}{4} \\ \\ x=4 \frac{1}{2}$

б)
$6 \frac{2}{3} -(x+ \frac{1}{4} )=2 \frac{1}{6} \\ \\6 \frac{2}{3} -x- \frac{1}{4} =2 \frac{1}{6} \\ \\ x=6 \frac{2}{3} -2 \frac{1}{6} - \frac{1}{4} \\ \\ x=6 \frac{8}{12} -2 \frac{2}{12} - \frac{3}{12} \\ \\ x=4 \frac{3}{12} \\ \\ x=4 \frac{1}{4}$