Question

$x_{2} x_{1 ^{2} } + x_{ 2^{2} } x_{1} \\ x^{2} + 4x+3 =0$

Answer 1

x²+4x+3=0
D=4²-4*3*1=16-12=4=2²
x₁=-4+2 / 2 = -2/2=-1
x₂=-4-2/2= -6/2=-3

x₂² x₁+ x₂ x₁²= (-3)² *(-1) + (-3)*(-1)²=-9-3=-12